2(9x-^)=6(3x-2)+2

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Solution for 2(9x-^)=6(3x-2)+2 equation: 



2(9x-^)=6(3x-2)+2

We move all terms to the left:

2(9x-^)-(6(3x-2)+2)=0

We multiply parentheses

18x-(6(3x-2)+2)+=0



We calculate terms in parentheses: -(6(3x-2)+2), so:

6(3x-2)+2

We multiply parentheses

18x-12+2

We add all the numbers together, and all the variables

18x-10

Back to the equation:

-(18x-10)



We add all the numbers together, and all the variables

18x-(18x-10)=0

We get rid of parentheses

18x-18x+10=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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